JEE Advance - Mathematics (1994 - No. 37)
If we consider only the principle values of the inverse trigonometric functions then the value of
$$\tan \left( {{{\cos }^{ - 1}}{1 \over {5\sqrt 2 }} - {{\sin }^{ - 1}}{4 \over {\sqrt {17} }}} \right)$$ is
$$\tan \left( {{{\cos }^{ - 1}}{1 \over {5\sqrt 2 }} - {{\sin }^{ - 1}}{4 \over {\sqrt {17} }}} \right)$$ is
$${{\sqrt {29} } \over 3}$$
$${{29} \over 3}$$
$${{\sqrt 3 } \over {29}}$$
$${3 \over {29}}$$