JAMB - Physics (2014 - No. 14)
A force of 500N1 is applied to a steel wire of cross-sectional area 0.2m2, The tensile stress is
2.5x104Nm-2
1.0x102Nm-2
1.0x103Nm-2
2.5x103Nm-2
คำอธิบาย
\(Stress = \frac{Force}{Area}\)
\(Stress = \frac{500}{0.2} = 2500\)
= 2.5 x 103Nm-3
\(Stress = \frac{500}{0.2} = 2500\)
= 2.5 x 103Nm-3