JAMB - Mathematics (2023 - No. 9)
Solve for x: 3(x – 1) ≤ 2 (x – 3)
x ≤ -3
x ≥ -3
x ≤ 3
x ≥ 3
คำอธิบาย
3(x – 1) ≤ 2 (x – 3)
= 3x – 3 ≤ 2x – 6
Add 3 to both sides
= 3x – 3+ 3 ≤ 2x – 6+ 3
= 3x ≤ 2x – 3
Subtract 2x from both the sides
= 3x – 2x ≤ 2x – 3 – 2x
∴ x ≤ -3
= 3x – 3 ≤ 2x – 6
Add 3 to both sides
= 3x – 3+ 3 ≤ 2x – 6+ 3
= 3x ≤ 2x – 3
Subtract 2x from both the sides
= 3x – 2x ≤ 2x – 3 – 2x
∴ x ≤ -3