JAMB - Mathematics (2019 - No. 27)
Solve for x in \(\frac{4x - 6}{3} \leq \frac{3 + 2x}{2}\)
\(x \leq 1\frac{1}{2}\)
\(x \leq \frac{21}{2}\)
\(x \geq \frac{21}{2}\)
\(x \geq 1\frac{1}{2}\)
คำอธิบาย
\(\frac{4x - 6}{3} \leq \frac{3 + 2x}{2}\)
2(4x - 6) \(\leq\) 3(3 + 2x)
8x - 12 \(\leq\) 9 + 6x
8x - 6x \(\leq\) 9 + 12
2x \(\leq\) 21
\(x \leq \frac{21}{2}\)