JAMB - Mathematics (2016 - No. 29)
Evaluate \(\int\limits_0^\frac{\pi}{2}\) sin xdx
2
-1
1
-2
คำอธิบาย
\(\int\limits_0^\frac{\pi}{2}\) sin xdx = -cosx|\(\frac{\pi}{2}\)
= -(cos\(\frac{\pi}{2}\) - cos0) = -(0-1) = 1
= -(cos\(\frac{\pi}{2}\) - cos0) = -(0-1) = 1