JAMB - Mathematics (2014 - No. 29)
If y = 4x3 - 2x2 + x, find \(\frac{\delta y}{\delta x}\)
8x2 - 2x + 1
8x2 - 4x + 1
12x2 - 2x + 1
12x2 - 4x + 1
คำอธิบาย
If y = 4x3 - 2x2 + x, then;
\(\frac{\delta y}{\delta x}\) = 3(4x2) - 2(2x) + 1
= 12x2 - 4x + 1
\(\frac{\delta y}{\delta x}\) = 3(4x2) - 2(2x) + 1
= 12x2 - 4x + 1