JAMB - Mathematics (1998 - No. 29)
Evaluate ∫\(^{\pi}_{2}\)(sec2 x - tan2x)dx
\(\frac{\pi}{2}\)
\(\pi\) - 2
\(\frac{\pi}{3}\)
\(\pi\) + 2
คำอธิบาย
∫\(^{\pi}_{2}\)(sec2 x - tan2x)dx
∫\(^{\pi}_{2}\) dx = [X]\(^{\pi}_{2}\)
= \(\pi\) - 2 + c
when c is an arbitrary constant of integration
∫\(^{\pi}_{2}\) dx = [X]\(^{\pi}_{2}\)
= \(\pi\) - 2 + c
when c is an arbitrary constant of integration