JAMB - Mathematics (1991 - No. 24)
Solve the equation (x - 2) (x - 3) = 12
2, 3
3, 6
-1, 6
1, -6
คำอธิบาย
(x - 2) (x - 3) = 12
x\(^2\) - 3x - 2x + 6 = 12
x\(^2\) - 5x - 6 = 0
(x +1)(x - 6) = 0
x = -1 or 6
x\(^2\) - 3x - 2x + 6 = 12
x\(^2\) - 5x - 6 = 0
(x +1)(x - 6) = 0
x = -1 or 6