JAMB - Mathematics (1991 - No. 13)
Evaluate \(\frac{xy^2 - x^2y}{x^2 - xy}\) When x = -2 and y = 3
3
-\(\frac{3}{5}\)
\(\frac{3}{5}\)
-3
คำอธิบาย
\(\frac{xy^2 - x^2y}{x^2 - xy^1}\)
= \(\frac{(-2)(3)^2 - (-2)^2(3)}{(-2)^2 - (-2)(3)}\)
= \(\frac{-30}{10}\)
= -3
= \(\frac{(-2)(3)^2 - (-2)^2(3)}{(-2)^2 - (-2)(3)}\)
= \(\frac{-30}{10}\)
= -3