JAMB - Mathematics (1987 - No. 11)
Evaluate without using tables (0.008) -\(\frac{1}{3}\) x (0.16) - \(\frac{3}{2}\)
\(\frac{625}{8}\)
\(\frac{8}{625}\)
\(\frac{1}{8}\)
8
คำอธิบาย
(0.008) -\(\frac{1}{3}\) x (0.16) - \(\frac{3}{2}\) = (8 x 10-3)10-3 x (16 x 10-2)-\(\frac{3}{2}\)
= \(\frac{(2^3)}{10^3}\) - 3 x \(\frac{(2^4)}{10}\) - \(\frac{-3}{2}\)
= \(\frac{625}{8}\)
= \(\frac{(2^3)}{10^3}\) - 3 x \(\frac{(2^4)}{10}\) - \(\frac{-3}{2}\)
= \(\frac{625}{8}\)