JAMB - Mathematics (1980 - No. 23)
Find the product of (2\(\sqrt{y} - 3y\)) and (3y + 2\(\sqrt{y}\))
4y = y2
4y + 9y2
4y - 9y2
-4y - 9y2
2y + y2
คำอธิบาย
(2\(\sqrt{y} - 3y\)) and (3y + 2\(\sqrt{y}\))
= 6y\(\sqrt{y}\) + 4y - 9y\(^2\) - 6y\(\sqrt{y}\)
= 4y - 9y\(^2\)
= 6y\(\sqrt{y}\) + 4y - 9y\(^2\) - 6y\(\sqrt{y}\)
= 4y - 9y\(^2\)