ExamPlay Dark Logo
เข้าสู่ระบบ

JAMB - Chemistry (2025 - No. 51)

On heating 12.5g of saturated solution to dryness at 60\(^0\)C, 2g of anhydrous salt was recovered, calculate its solubility in grams per 100g of water.
16.0
4.0
2.0
20.0

คำอธิบาย

Solubility is expressed as the mass of solute per 100g of solvent. It can be expressed mathematically below as:

Solubility = \(\frac{mass of solute}{mass of solvent}\) x \(\frac{100}{1}\)

= \(\frac{mass of salt}{mass of water}\) x \(\frac{100}{1}\)

Mass of salt = 2g

Mass of water = Mass of solution - mass of salt = 12.5 - 2 = 10.5g

Solubility = \(\frac{2}{10.5}\) x \(\frac{100}{1}\)

= 19.0476

= 19.05 g

ความคิดเห็น (0)

เข้าสู่ระบบเพื่อแสดงความคิดเห็น
โฆษณา
BrainBehindX Inc Logo
©2026; ขับเคลื่อนโดย BrainBehindX Inc