JAMB - Chemistry (2004 - No. 25)

The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is
[Ag = 108, 1F = 96500 Cmol-1]

108.0g

54.0g

27.0g

13.5g

Ag\(^+\) + e\(^-\) → Ag
If 96500 C deposited 108g of Ag
∴ 10 x 4830C will deposit Xg of Ag
X = \(\frac{{108}\times{4830}\times{10}}{96500}\)

X = 54.06g