JEE Advance - Mathematics (2006 - No. 26)
One angle of an isosceles $$\Delta $$ is $${120^ \circ }$$ and radius of its incircle $$ = \sqrt 3 $$. Then the area of the triangle in sq. units is
$$7 + 12\sqrt 3 $$
$$12 - 7\sqrt 3 $$
$$12 + 7\sqrt 3 $$
$$4\pi $$