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JEE Advance - Mathematics (1996 - No. 22)
General value of $$\theta $$ satisfying the equation $${\tan ^2}\theta + \sec \,2\,\theta = 1$$ is _________.
$$n\pi$$
$$n\pi + \frac{\pi}{3}$$
$$n\pi - \frac{\pi}{3}$$
$$2n\pi$$
$$n\pi \pm \frac{\pi}{3}$$
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