JAMB - Physics (2024 - No. 74)
The quantity of heat required to melt ice of 0.2 kg whose specific latent heat is 3.4 x 10\(^5\)J/Kg is
6.8 x 10\(^4\)J
8.6 x 10\(^4\)J
1.7 x 10\(^5\)J
1.7 x 10\(^6\)J
Maelezo
The quantity of heat required to melt ice = mass of ice x specific latent heat
Q = m L = 0.2 x 3.4 x 10\(^5\) = 6.8 x 10\(^4\)J