JAMB - Physics (2006 - No. 45)
An engine of a car of power 80 kW moves on a rough road with a velocity of 32 m\(s^-1\). The forces required to bring it to rest is
2.56 x 106N
2.50 x 106N
2.80 x 103N
2.50 x 103N
Maelezo
Power = force x velocity
=> 80,000 = F x 32
F = \(\frac{80000}{32}\)
= 2500N
= 2.50 x \(10^3\)N