JAMB - Physics (1998 - No. 15)
A solid of weight 0.600N is totally immersed in oil and water respectively. If the upthrust of oil is 0.210N and the relative density of oil is 0.875. Find the upthrust in water.
0.600N
0.360N
0.240N
0.180N
Maelezo
Rd = \(\frac{\text{upthrust in oil}}{\text{upthrust in }H_2O}\)
thus; 0.875 = \(\frac{0.21}{\text{upthrust in }H_2O}\)
upthrust in H2O = 0.24N
thus; 0.875 = \(\frac{0.21}{\text{upthrust in }H_2O}\)
upthrust in H2O = 0.24N