Ingia
JAMB - Physics (1995 - No. 9)
The energy contained in a wire when it extended by 0.02m by a force 500 N is
5J
10J
10
3
J
10
4
Maelezo
Energy = \(\frac{1}{2}\)Fe
= \(\frac{1}{2}\) x 500 x 0.02
E = 5J
Maoni (0)
Ingia Ili Kutoa Maoni
Tangazo
Ruhusu javascript kupakia vizuri ukurasa huu
