JAMB - Physics (1992 - No. 5)
A stone, Q is thrown with velocity U at an angle of 75o to the horizontal. Another stone R is thrown with the same velocity U but with an angle of 15o to the horizontal. The ranges covered by the stones will be
greater for Q
greater for R
the same for Q and R
greater for the heavier of the two stones
Maelezo
Range = \(\frac{U^2sin2\theta}{g}\)
RangeQ = \(\frac{U^2sin150}{g}\)
RangeR = \(\frac{U^2sin30}{g}\)
Since, sin30o = sin150o
therefore, RQ = RR
RangeQ = \(\frac{U^2sin150}{g}\)
RangeR = \(\frac{U^2sin30}{g}\)
Since, sin30o = sin150o
therefore, RQ = RR