JAMB - Physics (1991 - No. 28)
A man hears his echo from a nearby hill 2s after he shouted. If the frequency of his voice is 260Hz and the wavelength is 1.29m, how far away is the hill?
330.0m
335.4m
660.0m
670.8m
Maelezo
v = \(\lambda\)F
260 x 1.29 =335.4ms-1
Echo time = \(\frac{2}{2}\) = 1sec.
distance = v x t
= 335.4 x 1 = 335.4m
260 x 1.29 =335.4ms-1
Echo time = \(\frac{2}{2}\) = 1sec.
distance = v x t
= 335.4 x 1 = 335.4m