JAMB - Mathematics (1986 - No. 45)
In the figure, \(\bigtriangleup\)PQT is isosceles. PQ = QT, SRQ = 35o, TPQ = 20o and PQR is a straight line.Calculate TSR
20o
55o
75o
140o
Maelezo
Given \(\bigtriangleup\) isosceles PQ = QT, SRQ = 35o
TPQ = 20o
PQR = is a straight line
Since PQ = QT, angle P = angle T = 20o
Angle PQR = 180o - (20 + 20) = 140o
TQR = 180o - 140o = 40o < on a straight line
QSR = 180o - (40 + 35)o = 105o
TSR = 180o - 105o
= 75o