WAEC - Mathematics (2009 - No. 22)
solve \(\frac{2x + 1}{6} - \frac{3x - 1}{4}\) = 0
1
\(\frac{1}{5}\)
-\(\frac{1}{5}\)
-1
Објашњење
\(\frac{2x + 1}{6} - \frac{3x - 1}{4}\) = 0
\(\frac{4(2n + 1) - 6(3x - 1)}{24}\) = 0
-10x + 10 = 0
-10x = -10
x = \(\frac{-10}{-10}\)
x = 1
\(\frac{4(2n + 1) - 6(3x - 1)}{24}\) = 0
-10x + 10 = 0
-10x = -10
x = \(\frac{-10}{-10}\)
x = 1