WAEC - Mathematics (2008 - No. 16)
The angles of a quadrilateral are (x + 10)o, 2yo, 90o and (100 - y)o, Find y in terms of x
y = 160 + x
y = 100 + x
y = 160 - x
y = x - 100
Објашњење
Sum of the angles in a quadrilateral = 360o
(x + 10o) + 2y + 90o + 100 - y = 360o
x + y + 200 = 360o
y = 360 - 200 - x
y = 160 - x
(x + 10o) + 2y + 90o + 100 - y = 360o
x + y + 200 = 360o
y = 360 - 200 - x
y = 160 - x