JEE Advance - Mathematics (1996 - No. 22)

General value of $$\theta $$ satisfying the equation $${\tan ^2}\theta + \sec \,2\,\theta = 1$$ is _________.

$$n\pi$$

$$n\pi + \frac{\pi}{3}$$

$$n\pi - \frac{\pi}{3}$$

$$2n\pi$$

$$n\pi \pm \frac{\pi}{3}$$