JEE Advance - Mathematics (1978 - No. 7)
Find the equation of the circle whose radius is 5 and which touches the circle $${x^2}\, + \,{y^2}\, - \,2x\,\, - 4y\, - 20 = 0\,$$ at the point (5, 5).
$${x^2}, + ,{y^2}, - ,18x,, - 16y, + 120 = 0,$$
$${x^2}, + ,{y^2}, + ,18x,, + 16y, + 120 = 0,$$
$${x^2}, + ,{y^2}, - ,18x,, - 16y, - 120 = 0,$$
$${x^2}, + ,{y^2}, + ,18x,, + 16y, - 120 = 0,$$
$${x^2}, + ,{y^2}, - ,16x,, - 18y, + 120 = 0,$$