JEE MAIN - Physics (2007 - No. 33)
A round uniform body of radius $$R,$$ mass $$M$$ and moment of inertia $$I$$ rolls down (without slipping) an inclined plane making an angle $$\theta $$ with the horizontal. Then its acceleration is
$${{g\,\sin \theta } \over {1 - M{R^2}/I}}$$
$${{g\,\sin \theta } \over {1 + I/M{R^2}}}$$
$${{g\,\sin \theta } \over {1 + M{R^2}/I}}$$
$${{g\,\sin \theta } \over {1 - I/M{R^2}}}$$
Објашњење
A uniform body of radius R, mass M and moment of inertia $$I$$
rolls down (without slipping) an inclined plane making an angle
θ with the horizontal. Then its acceleration is
$$a = {{g\,\sin \,\theta } \over {1 + {I \over {M{R^2}}}}}$$
$$a = {{g\,\sin \,\theta } \over {1 + {I \over {M{R^2}}}}}$$