JAMB - Physics (2018 - No. 48)
An object is placed 20cm from a concave mirror of focal length 10cm. The linear magnification of the image produced is?
0
\(\frac{1}{2}\)
1
2
Објашњење
\(\frac{I}{V}\) = \(\frac{1}{f}\) – \(\frac{1}{u}\)
\(\frac{I}{V}\) = \(\frac{1}{10}\) – \(\frac{1}{20}\)
= \(\frac{1}{20}\) V
V = 20cm.
M = \(\frac{V}{U}\)
= \(\frac{20}{20}\)
= 1