JAMB - Physics (1979 - No. 7)
If in a simple pendulum experiment the length of the inextensible string is increased by a factor of four, its period is increased by a factor of
4
\(\frac{\pi}{2}\)
\(\frac{1}{4}\)
2\(\pi\)
2
Објашњење
In simple pendulum, T = 2\(\pi\)\(\sqrt\frac{L}{g}\)
\(\frac{T_2}{T_1}\) = \(\sqrt\frac{L_1}{L_2}\) but, L2 = 4L1
\(\frac{T_2}{T_1}\) = \(\sqrt\frac{L_1}{4L_1}\)
T2 = 4T1
\(\frac{T_2}{T_1}\) = \(\sqrt\frac{L_1}{L_2}\) but, L2 = 4L1
\(\frac{T_2}{T_1}\) = \(\sqrt\frac{L_1}{4L_1}\)
T2 = 4T1