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JAMB - Mathematics (2006 - No. 34)

In the diagram above, PQ = 10 cm, PS = 8 cm and ∠PSR is 60o while ∠SRQ is a right angle. Find SR
14 cm
14√3 cm
10 cm
10√3 cm

Објашњење

In ΔPST; cos 60 = ST/8
ST = 8cos 60
ST = 8 x 1/2 = 4
TR = 10 cm (opp. sides of a rectangle PQRT)
SR = ST + TR
SR = 4 + 10
SR = 14 cm

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