JAMB - Mathematics (1992 - No. 4)
What is the value of x satisfying the equation \(\frac{4^{2x}}{4^{3x}}\) = 2?
-2
-\(\frac{1}{2}\)
\(\frac{1}{2}\)
2
Објашњење
\(\frac{4^{2x}}{4^{3x}}\) = 2
42x - 3x = 2
4-x = 2
(22)-x
= 21
Equating coefficients: -2x = 1
x = -\(\frac{1}{2}\)
42x - 3x = 2
4-x = 2
(22)-x
= 21
Equating coefficients: -2x = 1
x = -\(\frac{1}{2}\)