JAMB - Chemistry (1990 - No. 42)
0.1 faraday of electricity deposited 2.95 g of nickel during electrolysis of an aqueous solution.
Calculate the number of moles of nickel that will be deposited by 0.4 faraday?
(Ni = 58.7)
Calculate the number of moles of nickel that will be deposited by 0.4 faraday?
(Ni = 58.7)
0.20
0.30
0.04
5.87
Објашњење
0.1F ↔ 2.95 g Ni = 0.4F ↔ 11.8 g Ni
No of moles = (11.8)/(58.2) = 0.20 moles
No of moles = (11.8)/(58.2) = 0.20 moles