ExamPlay Light Logo
Hyni

JAMB - Physics (1994 - No. 33)

A capacitor 8\(\mu\)F is charged to a potential difference of 100V. The energy stored by the capacitor is
1.0 x 104J
8.0 x 10J
1.25 x 10J
4.0 x 10-2J

Shpjegimi

Energy = \(\frac{1}{2}\)CV2

= \(\frac{1}{2}\) x 8 x 10-6 x (100)2

= 4 x 10-2J

Komentet (0)

Identifikohu për të komentuar
Reklamim
BrainBehindX Inc Logo
©2026; Mundësuar nga BrainBehindX Inc