JAMB - Physics (1978 - No. 22)
Three 5 ohms resistors connected in parallel have a potential difference of 60v. applied across the combination. The current in each resistor is
4A
36A
12A
24A
10A
Shpjegimi
since they are in parallel, the same voltage across
= I1 = I2 = I3
I1 = \(\frac{V}{R_1}\)
\(\frac{60}{5}\) = 12A
= I1 = I2 = I3
I1 = \(\frac{V}{R_1}\)
\(\frac{60}{5}\) = 12A