JAMB - Mathematics (2007 - No. 40)
A man 40 m from the foot of a tower observes the angle of elevation of the tower to be 30º. Determine the height of the tower.
\(\frac{40\sqrt{3}}{3}m\)
20 m
40√3 m
40 m
Shpjegimi
Tan 30 = \(\frac{h}{40}\)
\(\frac{1}{\sqrt{3}}=\frac{h}{40}\)
h\(\sqrt{3}\) = 40
h = \(\frac{40}{\sqrt{3}}\)
h = \(\frac{40}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}\)
h = \(\frac{40\sqrt{3}}{3}\)