JAMB - Mathematics (1995 - No. 28)
A school boy lying on the ground 30m away from the foot of a water tank tower observes that the angle of elevation of the top of the tank 60o. Calculate the height of the water tank.
60m
30 \(\sqrt{3}\)m
20 \(\sqrt{3}\)m
10 \(\sqrt{3}\)m
Shpjegimi
h = 30 tan 60o
= 30\(\sqrt{3}\)
= 30\(\sqrt{3}\)