WAEC - Mathematics (2014 - No. 2)
If 23x = 325, find the value of x
7
6
5
4
Vysvetlenie
23x = 325
2 \(\times x^1 + 3 \times x^0 = 3 \times 5^1 + 2 \times 5^0\)
= 2x + 3 = 15 + 2
2x + 3 = 17
2x = 17 - 3
2x = 14
x = \(\frac{14}{2}\)
x = 7
2 \(\times x^1 + 3 \times x^0 = 3 \times 5^1 + 2 \times 5^0\)
= 2x + 3 = 15 + 2
2x + 3 = 17
2x = 17 - 3
2x = 14
x = \(\frac{14}{2}\)
x = 7