JEE Advance - Physics (1979)

• 1

  The dispalcement x of particle moving in one direction, under the action of a constant force is related to the time t by the equation $$t = \sqrt x + 3$$
  where x is in meters and t in seconds. Find

  (i) The displacement of the particle when its velocity is zero, and

  (ii) The work done by the force in the first 6 seconds.

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  (A)

  Displacement is 0m when velocity is zero, and work done in the first 6 seconds is 0J
• 2

  Answer the following giving reason in brief:

  Is the time variation of position, shown in the figure observed in nature?

  

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  (C)

  No, it's not possible because an object cannot be at two different positions at the same time.