JEE MAIN - Chemistry (2003 - No. 59)
The de Broglie wavelength of a tennis ball of mass 60 g moving with a velocity of 10 meters per second is approximately
10-31 meters
10-16 meters
10-25 meters
10-33 meters
Объяснение
As per de-Broglie wavelength of a particle is
Wavelength ($$\lambda $$) = $${h \over {mv}}$$
Where h is plank's constant, m is mass of the particle and v is the velocity of the particle
$$\therefore \lambda $$ = $${{6.63 \times {{10}^{ - 34}}} \over {0.06 \times 10}}$$
= $${{6.63 \times {{10}^{ - 34}} \times 10} \over {0.6 \times 10}}$$
= $${{6.63 \times {{10}^{ - 33}}} \over 6}$$
$$ \cong 10{}^{ - 33}$$
Wavelength ($$\lambda $$) = $${h \over {mv}}$$
Where h is plank's constant, m is mass of the particle and v is the velocity of the particle
$$\therefore \lambda $$ = $${{6.63 \times {{10}^{ - 34}}} \over {0.06 \times 10}}$$
= $${{6.63 \times {{10}^{ - 34}} \times 10} \over {0.6 \times 10}}$$
= $${{6.63 \times {{10}^{ - 33}}} \over 6}$$
$$ \cong 10{}^{ - 33}$$