JAMB - Mathematics (2006 - No. 14)
Evaluate \(\int_{-4}^0(1 - 2x)dx\)
-16
-20
20
10
Объяснение
\(\int_{-4}^0(1 - 2x)\)dx = \([x - x^2]_{-4}^0\) = (0 - 0 + C) - (-4 - (-4)\(^2\) + C)
= C - ( - 4 - 16 +C )
= C - ( - 20 + C)
= C + 20 - C
= 20
= C - ( - 4 - 16 +C )
= C - ( - 20 + C)
= C + 20 - C
= 20