WAEC - Mathematics (2004 - No. 27)
In the diagram, KS is a tangent to the circle centre O at R and ∠ROQ = 80º. Find ∠QRS.
90o
80o
50o
40o
Explicaţie
QOP = 180 - 100(straight line angle) → 80°
OPQ and OQP are isosceles of 40° each.
∠QRS = ∠RPQ (theorem: angle in the alternate segment are equal)
∠RPQ = 40º
∠QRS = 40º