JAMB - Mathematics (1997 - No. 34)

Integrate \(\frac{1}{x}\) + cos x with respect to x

-\(\frac{1}{x^2}\) + sin x + k

x + sin x - k

x - sin x + k

-\(\frac{1}{x^2}\) - sin x + k

Explicaţie

\(\int \frac{1}{x} + \cos x = ln x - \sin x + k\)

Comentarii (0)

Publicitate