WAEC - Physics (2024 - No. 20)
A particle of mass 3.6 x 10\(^{-6}\)kg revolving around the earth has a radial acceleration of 4.3 x 10\(^7\)ms\(^{-2}\). Calculate the centripetal force of the particle.
1.55 x 10\(^2\)N
2.00 x 10\(^{-2}\)N
6.25 x 10\(^{-14}\)N
1.00 x 10\(^2\)N
Explanation
F = mass x acceleration due to gravity
F\(_c\) = m x a\(_c\)
a\(_c\) = a\(_r\) = 4.3 x 10\(^7\)ms\(^{-2}\), m = 3.6 x 10\(^{-6}\)kg
F\(_c\) = m x a\(_c\) = 3.6 x 10\(^{-6}\) x 4.3 x 10\(^7\) = 154.8N ≈ 155N ⇒ 1.55 x 10\(^2\)N
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