WAEC - Physics (2023 - No. 18)
A ball of mass 0.8 kg is dropped from a height, H. Just before hitting the ground, its velocity is 5.0 m/s. Determine H.
[g = 10 ms-2]
[g = 10 ms-2]
1.25m
4.00m
6.25m
1.60m
Explanation
u = 0, g = 10 \(ms^2\), v = 5 m/s, h = ?
From \(v^2 = u^2 + 2gh\)
ā \(5^2 = 0^2 + 2 Ć 10 Ć h\)
25 = 0 + 20h
25 = 20h
Therefore, h = \(\frac{25}{20}\) = 1.25m
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