WAEC - Physics (2023 - No. 12)
The most appropriate value of fuse for a kettle rated 220 V, 1.06 kW is
3A
6A
5A
4A
Explanation
V = 220V, P = 1.60KW = 1060W, I = ?
P = IV
I = \(\frac{P}{V} = \frac{1060}{220}\)
ā 5A.
Comments (0)
V = 220V, P = 1.60KW = 1060W, I = ?
P = IV
I = \(\frac{P}{V} = \frac{1060}{220}\)
ā 5A.
