WAEC - Physics (2022 - No. 26)
.An inductor of inductance 10 H is connected across an a.c circuit source of 50 V, 100 Hz. What is the current in the circuit? [\(\pi\) = 3.14]
0.200A
0.070A
0.050A
0.008A
Explanation
Given Data: L = 10, V = 50, F = 100, I = ?
Inductive Reactance [X\(_L\)] = 2\(\pi\)FL → 2 * 3.14 * 100 * 10
X\(_L\) = 6,280
Current[I] = \(\frac{V}{X_L}\) → \(\frac{50}{6280}\)
I = 0.0079
≈ 0.008A
Comments (0)
