Given that refractive index = 1.5, angle of incidence = 30°, angle of refraction =?

using snell's law = refractive index = \(\frac{sini}{sinr}\)

=\(\frac{1}{n } = \frac{sin30}{sinr}\)

= \(sinr = 1.5\times sin 30\)

r = \(sin^10.75\)

= 48.6° 

this is because ray is traveling from a more denser medium to a less dense medium