WAEC - Physics (2014 - No. 39)
A 15 \(\mu F\) capacitor is connected to a 240V, 50Hz ac. source. Calculate the reactance of the capacitance [\(\pi = 3.142\)]
16\(\Omega\)
68\(\Omega\)
106\(\Omega\)
212\(\Omega\)
Explanation
\(X_c = \frac{1}{2 \pi fc}\)
= 2 x 3.142 x 50 x 15 x 10-6
= 212.179\(\Omega\)
= 2 x 3.142 x 50 x 15 x 10-6
= 212.179\(\Omega\)
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