WAEC - Physics (2014 - No. 31)

an observer hears an echo 1.26 seconds after blowing a whistle near a cliff. calculate the distance of the observer from the cliff. [speed of sound in air = 330ms-1]
104.4m
207.9m
415.8m
523.8m

Explanation

S = \(\frac{vt}{2} = \frac{330 \times 1.26}{2} = 207.9\)

Comments (0)

Advertisement