WAEC - Physics (2013 - No. 31)
A charge of 2.0 x 10\(^{-5}\) C experiences a force of 80N in a uniform electric field. Calculate the magnitude of the electric field intensity
8.0 x 106 NC-1
4.0 x 106 NC-1
4.0 x 104 NC-1
2.0 x 104 NC-1
Explanation
E = \(\frac{F}{Q} = \frac{80}{2 \times 10^{-5}}\)
= 4 x 10\(^6\) NC\(^{-1}\)
= 4 x 10\(^6\) NC\(^{-1}\)
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